Optimal. Leaf size=61 \[ -\frac{15 \cot (a+b x)}{8 b}+\frac{\cos ^4(a+b x) \cot (a+b x)}{4 b}+\frac{5 \cos ^2(a+b x) \cot (a+b x)}{8 b}-\frac{15 x}{8} \]
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Rubi [A] time = 0.0455062, antiderivative size = 61, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 17, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.235, Rules used = {2591, 288, 321, 203} \[ -\frac{15 \cot (a+b x)}{8 b}+\frac{\cos ^4(a+b x) \cot (a+b x)}{4 b}+\frac{5 \cos ^2(a+b x) \cot (a+b x)}{8 b}-\frac{15 x}{8} \]
Antiderivative was successfully verified.
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Rule 2591
Rule 288
Rule 321
Rule 203
Rubi steps
\begin{align*} \int \cos ^4(a+b x) \cot ^2(a+b x) \, dx &=-\frac{\operatorname{Subst}\left (\int \frac{x^6}{\left (1+x^2\right )^3} \, dx,x,\cot (a+b x)\right )}{b}\\ &=\frac{\cos ^4(a+b x) \cot (a+b x)}{4 b}-\frac{5 \operatorname{Subst}\left (\int \frac{x^4}{\left (1+x^2\right )^2} \, dx,x,\cot (a+b x)\right )}{4 b}\\ &=\frac{5 \cos ^2(a+b x) \cot (a+b x)}{8 b}+\frac{\cos ^4(a+b x) \cot (a+b x)}{4 b}-\frac{15 \operatorname{Subst}\left (\int \frac{x^2}{1+x^2} \, dx,x,\cot (a+b x)\right )}{8 b}\\ &=-\frac{15 \cot (a+b x)}{8 b}+\frac{5 \cos ^2(a+b x) \cot (a+b x)}{8 b}+\frac{\cos ^4(a+b x) \cot (a+b x)}{4 b}+\frac{15 \operatorname{Subst}\left (\int \frac{1}{1+x^2} \, dx,x,\cot (a+b x)\right )}{8 b}\\ &=-\frac{15 x}{8}-\frac{15 \cot (a+b x)}{8 b}+\frac{5 \cos ^2(a+b x) \cot (a+b x)}{8 b}+\frac{\cos ^4(a+b x) \cot (a+b x)}{4 b}\\ \end{align*}
Mathematica [A] time = 0.138363, size = 41, normalized size = 0.67 \[ -\frac{16 \sin (2 (a+b x))+\sin (4 (a+b x))+32 \cot (a+b x)+60 a+60 b x}{32 b} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.011, size = 66, normalized size = 1.1 \begin{align*}{\frac{1}{b} \left ( -{\frac{ \left ( \cos \left ( bx+a \right ) \right ) ^{7}}{\sin \left ( bx+a \right ) }}- \left ( \left ( \cos \left ( bx+a \right ) \right ) ^{5}+{\frac{5\, \left ( \cos \left ( bx+a \right ) \right ) ^{3}}{4}}+{\frac{15\,\cos \left ( bx+a \right ) }{8}} \right ) \sin \left ( bx+a \right ) -{\frac{15\,bx}{8}}-{\frac{15\,a}{8}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.48495, size = 85, normalized size = 1.39 \begin{align*} -\frac{15 \, b x + 15 \, a + \frac{15 \, \tan \left (b x + a\right )^{4} + 25 \, \tan \left (b x + a\right )^{2} + 8}{\tan \left (b x + a\right )^{5} + 2 \, \tan \left (b x + a\right )^{3} + \tan \left (b x + a\right )}}{8 \, b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.84227, size = 135, normalized size = 2.21 \begin{align*} \frac{2 \, \cos \left (b x + a\right )^{5} + 5 \, \cos \left (b x + a\right )^{3} - 15 \, b x \sin \left (b x + a\right ) - 15 \, \cos \left (b x + a\right )}{8 \, b \sin \left (b x + a\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 4.80812, size = 119, normalized size = 1.95 \begin{align*} \begin{cases} - \frac{15 x \sin ^{4}{\left (a + b x \right )}}{8} - \frac{15 x \sin ^{2}{\left (a + b x \right )} \cos ^{2}{\left (a + b x \right )}}{4} - \frac{15 x \cos ^{4}{\left (a + b x \right )}}{8} - \frac{15 \sin ^{3}{\left (a + b x \right )} \cos{\left (a + b x \right )}}{8 b} - \frac{25 \sin{\left (a + b x \right )} \cos ^{3}{\left (a + b x \right )}}{8 b} - \frac{\cos ^{5}{\left (a + b x \right )}}{b \sin{\left (a + b x \right )}} & \text{for}\: b \neq 0 \\\frac{x \cos ^{6}{\left (a \right )}}{\sin ^{2}{\left (a \right )}} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.24547, size = 74, normalized size = 1.21 \begin{align*} -\frac{15 \, b x + 15 \, a + \frac{7 \, \tan \left (b x + a\right )^{3} + 9 \, \tan \left (b x + a\right )}{{\left (\tan \left (b x + a\right )^{2} + 1\right )}^{2}} + \frac{8}{\tan \left (b x + a\right )}}{8 \, b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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